algebra
posted by Anonymous .
Perimeter of a rectangle. The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width.

original length = x
original width = 3x/4
2(x+2) + 2(3x/4 + 2) = 50
2x + 4 + 3x/2 + 4 = 50
times 2
4x + 8 + 3x + 8 = 100
7x = 84
x = 12
length = 12
width = 9