Posted by gin on Saturday, March 12, 2011 at 11:26pm.
You need to explain the problem a little better. Is that the NH4HS system in equilibrium at 25C and the 5.00 L flask is charged with enough H2S to make 0.4 kg H2S? Or is that an additional 0.4 kg H2S is added to the equilibrium mixture? The way the sentence is structured says that you are placing 0.4 g H2S is a 5.00 L flask. Of course, no NH4HS can come out of that.
Initial pressure H2S is
moles H2S = 0.4/molar mass H2S.
Use PV = nRT and solve for partial pressure of H2S.
Related Questions
chemistry - Ammonium bisulfide, NH2HS, forms ammonia NH3, and hydrogen sulfide, ...
AP CHEM - I would really appreciate some help on this problem. =) At 218 C, Kc...
chem - Consider the decomposition of ammonium hydrogen sulfide: NH4Hs(s) <...
chemistry, plz check work - NH3+H2S-->NH4HS <-- Kc=400 at 35 ...
chem - The decomposition of ammonium hydrogen sulfide that is shown below is an ...
Chemistry - For the following reaction, the equilibrium constant KC = 97.0 at ...
Chemistry - For the following reaction, the equilibrium constant KC = 97.0 at ...
Chemistry - For the following reaction, the equilibrium constant Kc = 97.0 at ...
chemistry - What is the pressure change for the reaction below at 25 C in the ...
chemistry - At 23°C, Kp = 0.075 for the equilibrium: NH4HS (s) ↔ ...
For Further Reading