Sunday

March 29, 2015

March 29, 2015

Posted by **Amie** on Saturday, March 12, 2011 at 10:37pm.

- calculus -
**Reiny**, Sunday, March 13, 2011 at 12:17amdy/dx = (2/3)(9-x^2)^(-1/3) (2x)

when x = 1, y = 8^(2/3) = 4

dy/dx = (2/3)(8)^(-1/3) (2)

= (4/3)((1/2) = 2/3

equation:

y = (2/3)x + b

at( 1,4)

4 = (2/3) + b

b = 10/3

y = (2/3)x + 10/3

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