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November 25, 2014

November 25, 2014

Posted by **mehak** on Saturday, March 12, 2011 at 9:29pm.

- calculus -
**Reiny**, Sunday, March 13, 2011 at 12:22amlet the horizontal distance from Quinton be x km

let the distance between plane and Quinto by y km

x^2 + 10^2 = y^2

2x dx/dt = 2y dy/dt

dy/dt = (x dx/dt)/y

when x=20

y^2 = 400 + 100 = 500

y = √500 = 10√5

dx/dt = 600 km/h

dy/dt = 20(600)/10√5 = appr. 536.7 km/h

- calculus -
**Mehak**, Sunday, March 13, 2011 at 12:42amBut did u use pythagoram theorom an how did u manipulate it ? And thanks because the answer is right .

- calculus -
**Reiny**, Sunday, March 13, 2011 at 12:51amyes, you can see in my first line of the solution that I used the Pythagorean theorem.

I then differentiate**with respect to time**, since we were talking about "rates" in the question and I saw a rate given as 600 km/h

- calculus -
**Mehak**, Sunday, March 13, 2011 at 1:09amThank you !

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