Saturday

April 19, 2014

April 19, 2014

Posted by **anon** on Saturday, March 12, 2011 at 7:09pm.

A.1/6 x^2 sin 3x + C

B.1/3 x sin 3x -1/2 sin 3x +C

C.1/3 x sin 3x +1/9 cos 3x +C << my choice.

D. 1/2 x^2 +1/18 sin^2 3x +C

2.evaluate (integral sign)xe(power of 2x)dx

A.1/6 x^2 e(to the power of 3x)+C

B.1/2 xe(to the power of 2x)-1/2 e(to

the power of 2x)+C

C.1/2xe(to the power of 2x) -1/4 e(to the power of 2x) +C

D.1/2 x^2 -1/8 e(to the power of 4x +C

I don't know the answer to this one.

- Calculus -
**MathMate**, Saturday, March 12, 2011 at 7:30pm1. C is Correct

Integration by parts,

∫xcos(3x)dx

=(1/3)xsin(3x)-(1/3)∫cos(3x)dx

= ....

2. Same as 1. Use integration by parts

∫xe^{2x}dx

=(1/2)xe^{2x}-(1/2)∫e^{2x}dx

=...

- Calculus -
**Anon**, Sunday, March 13, 2011 at 5:30amC ?

- Calculus -
**MathMate**, Sunday, March 13, 2011 at 9:50amPerfect!

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