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Posted by **pamela** on Saturday, March 12, 2011 at 4:00pm.

- math -
**bobpursley**, Saturday, March 12, 2011 at 4:04pmfactors of 435: 5 (87) so five folks one 27 committees. (or 87 folks [not allowed] one 5 committees).

factors of 435: 15 (29) would that work? 15 folks on 29 committees?

Any others?

- math -
**judy williams**, Sunday, July 3, 2011 at 3:08pmSuppose the 435 members of the House of Representatives

are placed on committees consisting of more than

2 members but fewer than 30 members. Each committee

is to have an equal number of members and each member

is to be on only one committee.

a. What size committees are possible?

b. How many committees are there of each size?

- math -
**Henry**, Monday, July 4, 2011 at 2:29pmM = Members.

C = Committees.

3M/C * 145C = 435 Members.

5M/C * 87C = 435.

15M/C * 29C = 435.

29M/C * 15C = 435.

a. 3,5,15,and 29M/C are possible.

b. 145,87,29, and 15C, respectively.

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