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February 1, 2015

February 1, 2015

Posted by **Abnerbell** on Saturday, March 12, 2011 at 3:29pm.

- calculus -
**bobpursley**, Saturday, March 12, 2011 at 3:41pmWhat is -3*e^-3x ? You ought to have this in your head, automatically.

f=e^ax

f'= a*e^ax

f"=a^2*e^ax

- calculus -
**Abnerbell**, Saturday, March 12, 2011 at 3:55pmThats what I thought but the negative threw me off. I didnt know if I needed to subtract 1 to remove the negative. Or if that mattered in this equation.

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