Posted by arty on Saturday, March 12, 2011 at 2:59pm.
what are the steps to solve for x
2x^21/x^2=0
 calculus  Damon, Saturday, March 12, 2011 at 3:04pm
2 x^2  1/x^2 = 0 ???
2 x^4 = 1
x^4 = 1/2
x^2 = (1/2)^.5 or (1/2)^.5
x = (1/2)^.25 or (1/2)^.25 or i(1/2)^.25 or i(1/2)^.25
 calculus  arty, Saturday, March 12, 2011 at 3:12pm
thank you.i am trying to sove for critical numbers. the book is giving me an answer of
x=+square root 2/2

 calculus  bobpursley, Saturday, March 12, 2011 at 3:56pm
I am wondering if the problem then is this:
(2x^21)/x^2=0
2x^2=1
x= + sqrt (1/2)
but of course, multiplying that by sqrt(2/2) one gets
x= + sqrt (2/4)= + .5 sqrt 2
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