r = 2nd/1st or 3rd/2nd
= (1/3) / 1 or (1/9) / (1/3)
= 1/3 for both
ar = 3
ar^4 = 81/8
divide the second equation by the first
r^3 = 27/8
r = 3/2
take it from there
3. to be a GS
y/x = 3/y
y^2 = 3x
that's all you can do, unless you know either x or y
128 , 128r , 128r^2 , 128r^3 , 128r^4 , 4
then 128r/128 = 4/(128r^4)
solve for r
5. you try it, it's easy.
The numbers 27;x;y are in geometric progression if the sum of these numbers is 21 calculate the possible value of x and y
Answer this Question
Maths - 1..The first 2 terms of a geometric progression are the same as the ...
Math (Geometric Progression) - 5 distinct positive reals form an arithmetic ...
Geometric progression - The second term of a geometric progression is 12 more ...
Math - 5 distinct positive reals form an arithmetic progression. The 1st, 2nd ...
math - If the sum of the first and the second terms of an infinite Geometric ...
Arithmetic - The first, second and third terms of a geometric progression are 2k...
Math Algebra - The first term of a geometric progression is more than the third ...
GP Caluculus - The third term of a geometric progression is 16. The sum of the ...
geometric progression - the 3rd term of a gpis 10 and the 6th term is 80 find ...
math - in a Geometric progression the sum of the first and the second terms is ...