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Posted by Anonymous on Saturday, March 12, 2011 at 9:00am.

prove that (sin^4x-cos^4x)/(sinx-cosx) = sinx+cosx

(sin^4x-cos^4x)/(sinx-cosx) =(sin^2x+cos^2x)(sin^2x-cos^2x)/(sinx-cosx) =1*(sinx+cosx)(sinx-cosx)/(sinx-cosx) =sinx+cosx

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