Posted by Anonymous on Saturday, March 12, 2011 at 9:00am.
(sin^4x-cos^4x)/(sinx-cosx)
=(sin^2x+cos^2x)(sin^2x-cos^2x)/(sinx-cosx)
=1*(sinx+cosx)(sinx-cosx)/(sinx-cosx)
=sinx+cosx
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