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February 1, 2015

February 1, 2015

Posted by **Anonymous** on Saturday, March 12, 2011 at 9:00am.

- trig -
**MathMate**, Saturday, March 12, 2011 at 9:24am(sin^4x-cos^4x)/(sinx-cosx)

=(sin^2x+cos^2x)(sin^2x-cos^2x)/(sinx-cosx)

=1*(sinx+cosx)(sinx-cosx)/(sinx-cosx)

=sinx+cosx

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