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February 28, 2015

February 28, 2015

Posted by **shasha** on Saturday, March 12, 2011 at 7:03am.

- Diff eqn- IVP -
**MathMate**, Saturday, March 12, 2011 at 10:22amThis is an IVP (initial value problem).

x"(t)=(6t-4) ms^{-2}....(1)

"...if the particle is at origin and has a velocity of**?**when t=0."

Integrate (1) with respect to t to find x'(t) and x(t). Do not forget the integration constants at each integration.

Use the initial conditions

x(0)=0 and x'(0)=(???)

to find C1 and C2 (int. constants).

When C1 and C2 are known, evaluate

x(3) and x'(3) as required.

- Diff eqn- IVP -
**shasha**, Saturday, March 12, 2011 at 5:45pmthanzz again

- Diff eqn- IVP :) -
**MathMate**, Sunday, March 13, 2011 at 7:27pm:)

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