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March 29, 2015

March 29, 2015

Posted by **Lost student** on Saturday, March 12, 2011 at 12:20am.

- Calculus -
**drwls**, Saturday, March 12, 2011 at 2:08amLet the distance of the bottom of the ladder from the wall be x, and let the distance of the top of the ladder from the floor be y.

x^2 + y^2 = 256

You want to know dy/dt when dx/dt = 3 and x = 2. At that time, y^2 = 252 and y = 15.87

2x *dx/dt + 2y*dy/dt = 0

dy/dt = -(x/y)*dx/dt = -0.126 dx/dt

Use that equation to calculate dy/dt

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