Posted by Lost student on Saturday, March 12, 2011 at 12:20am.
Let the distance of the bottom of the ladder from the wall be x, and let the distance of the top of the ladder from the floor be y.
x^2 + y^2 = 256
You want to know dy/dt when dx/dt = 3 and x = 2. At that time, y^2 = 252 and y = 15.87
2x *dx/dt + 2y*dy/dt = 0
dy/dt = -(x/y)*dx/dt = -0.126 dx/dt
Use that equation to calculate dy/dt
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