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September 30, 2014

September 30, 2014

Posted by **Esther** on Friday, March 11, 2011 at 10:43pm.

(10bf)/(b^2-f^2)-(b-f)/b+f)

Thank you for your help

- Algebra 2 -
**Europia**, Wednesday, March 30, 2011 at 3:22pmthe actual subtraction part is easy: it's two factions being subtracted, which can only be done if they have the SAME denominator. So... the common denominator for the new fraction will be

(b^2 - f^2)(b + f)

the numerator is

(10bf)*(b + f) - (b - f)*(b^2 - f^2)

the new fraction is

(10bf)*(b + f) - (b - f)*(b^2 - f^2)

-----------------------------------

(b^2 - f^2)(b + f)

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