Posted by Rachel on Friday, March 11, 2011 at 10:32pm.
Since the masses are in a 1:5 ratio, and the total momentum remains zero, the large mass will have 1/5 the velocity of the smaller mass at all times.
They collide when the separation distance is d = r1 + r2 = 5.6*10^6 m
At that time, the total kinetic energy equals the potential energy loss, which is
KE = G*M1*M2/d
With 1/5 of the mass of M2, M1 will have 5 times the velocity and 5 times its kinetic energy, giving it 5/6 of the total KE. M2 will have the other 1/6.
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