Posted by Rachel on Friday, March 11, 2011 at 7:35pm.
A system consists of three particles, each of mass 2.10 g, located at the corners of an equilateral triangle with sides of 22.0 cm.
Calculate the potential energy of the system.
Please help me what formula to use please
physics - drwls, Friday, March 11, 2011 at 7:50pm
Relative to a situation where the masses are widely separated, the potential energy of the equilateral configuration will be negative. That is because it will require work to separate them.
A single mass m has no potential associated with it.
When you add a second mass m at distance a, there will potential anergy equal to
When you bring in a third mass m at distance a from both, you add potential energy equal to -2G m^2/a
The total potential energy is therefore
G is the universal constant of gravity, m = 0.0021 kg and a = 0.22 m
Expect a very small number.
physics - drwls, Friday, March 11, 2011 at 7:59pm
The constant G can be found at
physics - Rachel, Friday, March 11, 2011 at 8:38pm
Thank you very much sir!
Answer This Question
More Related Questions
- science[physics] - three masses 3kg,4kg,5kg are located at corners of an ...
- Physics - We study the three point charges. They are held at the corners of an ...
- Physics 212 - Three equal point charges, each with charge 1.50\mu C , are placed...
- physics - Three particles of masses 14 kg, 21 kg, and 69 kg are located at the ...
- Physics - Three positive particles of equal charge +11.o micro C, are located at...
- Physics - A charge of q1=1×10−6 C is located at corner A of an equilateral...
- trig/physics - Three positive particles of equal charge +11.o micro C, are ...
- Physics - a system consists of four particles how many terms appear in the ...
- Physics - We study the three point charges shown in the figure. They are held at...
- Physics - A system consists of two particles. Particle 1 with mass 2.0 kg is ...