Posted by **Shannon** on Friday, March 11, 2011 at 7:33pm.

Find constants a and b in the equation f(x)= ax^b/(ln(x)) such that f(1/8)= 1 and the function has a local minimum at x= 1/8

- Calculus -
**Alyssa**, Friday, March 11, 2011 at 7:47pm
a=-0.7650

b=-0.4809

- Calculus -
**Reiny**, Friday, March 11, 2011 at 11:16pm
I concur

## Answer this Question

## Related Questions

- Calculus 1 - Find constants a and b in the equation f(x)= ax^b/(ln(x)) such ...
- Calculus - Find constants a and b in the function f(x)=axbln(x) such that f(15...
- Calculus - Find constants a and b in the function f(x)=(ax^b)ln(x) such that f(...
- calculus - Find constants a and b in the function f(x)=ax^b/(ln(x)) such that f(...
- Calculus - Functions? - #1. A cubic polynomial function f is defined by f(x) = ...
- Calculus - Find constants a and b in the function f(x)=axe^(bx)such that f(1/7)=...
- Calculus - Find constants a and b in the function f(x)=axe^(bX) such that f(1/8...
- Calculus - Find constants a and b in the function ax^b/ln(x) such that f(1/5)=1 ...
- Calculus (pleas help!) - Find constants a and b in the function f(x)=axe^bx such...
- calculus - A cubic polynomial function f is defined by f(x)= 4x^3+ab^2+bx+k ...

More Related Questions