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December 17, 2014

December 17, 2014

Posted by **Esther** on Friday, March 11, 2011 at 5:04pm.

(10bf)/(b^2-f^2)-(b-f)/b+f)

Thank you for your help

- Algebra 2 -
**Damon**, Friday, March 11, 2011 at 5:07pmhint

b^2-f^2 = (b-f)(b+f)

- Algebra 2 -
**Esther**, Friday, March 11, 2011 at 5:22pmSo, is the answer (b-f)(b+f)? which I think goes at the bottom as a fraction, and if it does, what is the number that goes on top?

However, I could be wrong, can you please help me understand? Thank you.

- Algebra 2 -
**MathMate**, Saturday, March 12, 2011 at 9:57am(10bf)/(b^2-f^2)-(b-f)/b+f)

=(10bf)/((b+f))(b-f)) - (b-f)/(b+f)

Now multiply second term top and bottom by (b-f) to get a common denominator

(10bf)/((b+f))(b-f)) - (b-f)(b-f)/((b+f)(b-f))

You can take it from here.

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