Posted by Esther on Friday, March 11, 2011 at 5:04pm.
hint
b^2-f^2 = (b-f)(b+f)
So, is the answer (b-f)(b+f)? which I think goes at the bottom as a fraction, and if it does, what is the number that goes on top?
However, I could be wrong, can you please help me understand? Thank you.
(10bf)/(b^2-f^2)-(b-f)/b+f)
=(10bf)/((b+f))(b-f)) - (b-f)/(b+f)
Now multiply second term top and bottom by (b-f) to get a common denominator
(10bf)/((b+f))(b-f)) - (b-f)(b-f)/((b+f)(b-f))
You can take it from here.
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