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March 25, 2017

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what is the derivative of:

y=2sinxcosx

  • Calculus - ,

    to ways to do it

    1. recognize that 2sinxcosx = sin(2x)
    then dy/dx = 2cos(2x)

    or

    2. y = 2sinxcosx
    dy/dx = 2sinx(-sinx) + 2cosx(cosx)
    = 2(cos^2x - sin^2x)
    which just happens to be 2cos(2x) as above

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