if 200.0 ml of 0.800 m is prepared from a 70.0 ml stock solution, what is the molarity of stock solution
you have diluted it 200/70 times, so the original solution was 200/70 * .8M
To find the molarity of the stock solution, you can use the formula:
M1V1 = M2V2
Where:
M1 = initial molarity of the stock solution
V1 = initial volume of the stock solution
M2 = final molarity of the diluted solution
V2 = final volume of the diluted solution
Given:
V1 (initial volume) = 70.0 ml
M2 (final molarity) = 0.800 M
V2 (final volume) = 200.0 ml
Plugging in the values into the formula, we have:
M1 * V1 = M2 * V2
M1 * 70.0 ml = 0.800 M * 200.0 ml
M1 = (0.800 M * 200.0 ml) / 70.0 ml
M1 ≈ 2.2857 M
Therefore, the molarity of the stock solution is approximately 2.286 M.
To find the molarity of the stock solution, we need to apply the formula for molarity:
M1 × V1 = M2 × V2
where M1 is the molarity of the stock solution, V1 is the volume of the stock solution, M2 is the molarity of the diluted solution, and V2 is the volume of the diluted solution.
In this case, we know that:
- V1 (volume of stock solution) is 70.0 mL
- V2 (volume of diluted solution) is 200.0 mL
- M2 (molarity of diluted solution) is 0.800 M
First, we rearrange the formula to solve for M1 (molarity of stock solution):
M1 = (M2 × V2) / V1
Now we can plug in the values:
M1 = (0.800 M × 200.0 mL) / 70.0 mL
M1 = 2.29 M
Therefore, the molarity of the stock solution is 2.29 M.