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August 31, 2014

August 31, 2014

Posted by **delilah** on Friday, March 11, 2011 at 1:14am.

- Calculus-implicit diff. -
**MathMate**, Friday, March 11, 2011 at 8:30amCheck that (6,5) lies on the curve by substituting x=6,y=5 and see if the equality holds. (yes, it holds).

Differentiate:

((Sqrt(x+3y)+sqrt(3xy))=(sqrt(21)+sqrt(90))

(1/2)/sqrt(x+3y)*(1+3y')+(1/2)/sqrt(3xy)*(3y+3xy')=0

transpose and cross multiply:

-sqrt(x+3y)*(1+3y')=sqrt(3xy)*(3y+3xy')

Solve for y'

y'(x,y)=-(sqrt(3*y+x)+3^(3/2)*y*sqrt(x*y))/(3*sqrt(3*y+x)+3^(3/2)*x*sqrt(x*y))

so

y'(6,5)=(-5*3^(3/2)*sqrt(30)-sqrt(21))/(2*3^(5/2)*sqrt(30)+3*sqrt(21))

=-0.796....

please check my arithmetic.

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