Wednesday

August 20, 2014

August 20, 2014

Posted by **Michelle** on Friday, March 11, 2011 at 12:13am.

2. Evaluate the integral by reversing the order of integration. double integral sqrt(2+x^3) dxdy... 1st integral (top=1, bottom=0)... 2nd (interior) integral(top=1, bottom=sqrt(y)).

3. Evaluated the integral using a change of variables; double integral sin(x+y) dxdy... below both integral signs is R... over the region R being on the disc x^2 +u^2<=2.

Thanks!

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