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January 29, 2015

January 29, 2015

Posted by **Esther** on Thursday, March 10, 2011 at 11:46pm.

(9p^b)/p^2-b^2 - p-b/p+b.

Thank you. These problems, I don't understand at all. I'm sorry.

- Algebra 2-parentheses -
**MathMate**, Friday, March 11, 2011 at 8:37amThe way the expression is typed is probably different from the book for lack of parentheses. When it is type-set, parentheses are not required on the numerator and denominator. When interpreted on one single line, they are required, or else a completely different expression results.

Also, I think 9p^b at the beginning should read 9p^2 (just a guess).

Please check what I assume is the correct interpretation.

(9p^2)/(p^2-b^2) - (p-b)/(p+b)

=(9p^2)/((p+b)(p-b)) - (p-b)²/((p+b)(p-b))

=(9p^2-(p-b)²)/((p+b)(p-b))

=(3p+p-b)(3p-(p-b))/((p+b)(p-b))

=(4p-b)(2p+b)/((p+b)(p-b))

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