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September 18, 2014

September 18, 2014

Posted by **cot** on Thursday, March 10, 2011 at 10:27pm.

g(2) = 5, g′(2) = -3, g′(-6) = -3, h(2) = -6,

and h′(2) = 4.

- math -
**drwls**, Friday, March 11, 2011 at 6:24amh(2) = -6

f'(2) = g'[h(2)] = g'(-6) = -3

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