A 12.1 g CD with a radius of 6.16 cm rotates with an angular speed of 31.1 rad/s. What is its kinetic energy?
Physics please help!! - Henry, Saturday, March 12, 2011 at 4:38pm
C=3.14 * 2 * 6.16cm = 38.68cm = 0.387m.
V = 31.1rad/s * (1/6.28)rev/rad * 0.387m/rev = 1.92m/s.
KE = 0.5mV^2 = 0.5*0.121kg*(1.92m/s) =
Physics please help!! - Henry, Saturday, March 12, 2011 at 4:43pm
Should be (1.92m/s)^2.