V= sqrt (6*re*9.8/36)
Period? Well, T=distance/velocity=2PI*6Re/above V
That will give the period in seconds, you probably want to convert it.
(a) centrieptal acceleration rate =
V^2/r = GM/r^2
where M is the mass of the earth and r = 6 Re.
Re is the radius of the earth that you were given
G is the universal constant of gravity.
Solve for V
V^2/(6 Re) = GM/(6Re)^2
You can save yourself the trouble of looking up M and G by using the relationship
g = GM/Re^2. Then
6 V^2 /Re = GM/Re^2 = g
V^2 = (Re*g/6)
V = 3230 m/s
(b) V*(period) = 2 pi R = 12 pi Re
Solve for the period
Vc = sqrt(µ/r) where µ = 3.9863x10^14 and r = 6378km.
Vc = sqrt[3.9863x10^14/6x6,378,000] =
The period derives from
T = 2(Pi)sqrt[r^3/µ]
physics - (a) Find the speed of a satellite moving around the earth in a ...
Physics - (a) Find the speed of a satellite moving around the earth in a ...
physics - Find the speed of a satellite in a circular orbit around the earth ...
PHYSÝCS - Find the speed of a satellite in a circular orbit around the Earth ...
physics - A 512 kg satellite is in a circular orbit about the Earth at a height ...
trig - In a computer simulation, a satellite orbits around Earth at a distance ...
Physics Meteorite - A satellite in a circular orbit around earth with a radius ...
geometry - A satellite in a nearly circular orbit is 2000 km above Earth's ...
physics - A 581 kg satellite is in a circular orbit about the Earth at a height ...
Physics - A spy satellite is in circular orbit around Earth. It makes one ...