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March 3, 2015

March 3, 2015

Posted by **tom** on Thursday, March 10, 2011 at 5:27pm.

- physics -
**Henry**, Saturday, March 12, 2011 at 12:31am30deg E of N = 60deg CCW.

X = hor = 49 + 27*cos60,

X=49 + 13.5=62.5km=hor comp. of vector.

Y = ver = 21 + 27*sin60,

Y = 21 + 23.38 = 44.38km.

a. D = sqrt(x^2 + y^2),

D = sqrt(3906.25+1969.58),

D = 76.7km.

b. tanA = Y/X = 44.38 / 62.5 = 0.7101.

A = 35.4 deg = Direction.

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