Posted by **tom** on Thursday, March 10, 2011 at 5:27pm.

A car is driven east for a distance of 49 km, then north for 21 km, and then in a direction 30° east of north for 27 km. Determine (a) the magnitude (in km) of the car's total displacement from its starting point and (b) the angle (from east) of the car's total displacement measured from its starting direction.

- physics -
**Henry**, Saturday, March 12, 2011 at 12:31am
30deg E of N = 60deg CCW.

X = hor = 49 + 27*cos60,

X=49 + 13.5=62.5km=hor comp. of vector.

Y = ver = 21 + 27*sin60,

Y = 21 + 23.38 = 44.38km.

a. D = sqrt(x^2 + y^2),

D = sqrt(3906.25+1969.58),

D = 76.7km.

b. tanA = Y/X = 44.38 / 62.5 = 0.7101.

A = 35.4 deg = Direction.

## Answer this Question

## Related Questions

- physics - A car is driven east for a distance of 49 km, then north for 35 km, ...
- physics - A car is driven east for a distance of 49 km, then north for 35 km, ...
- physics - A car is driven east for a distance of 88 km, then north for 28 km, ...
- physics - A car is driven east for a distance of 50 km, then north for 30 km, ...
- Science - A car is driven east for a distance of 43 km, then north for 20 km, ...
- physics - A car is driven east for a distance of 45 km, then north for 33 km, ...
- Physics - A car is driven east for a distance of 46 km, then north for 27 km, ...
- Physics - A car is driven east for a distance of 46 km, then north for 29 km, ...
- physics - A car is driven east for a distance of 41 km, then north for 21 km, ...
- physics - A car is driven east for a distance of 42 km, then north for 25 km, ...

More Related Questions