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A photogrpaher points a camera at a windows in a nearby building forming an angle of 42 degrees with the camera platform. If the camera is 52 meters from the building , how high above the platform is the window, to the nearest hundreth of a meter.

The answer is 46.82m, i would like to the steps/work for getting this answer...thanks in advance

  • Pre-Calculus -

    Draw a rt triangle and label the hor side 52m. Label the ver side h; and
    label the angle between the hor side
    and hyp. 42 deg.

    tan42 = h/52,
    Cross multiply:
    h = 52*tan42 = 46.82m.

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