A block of weight 200N rest on a rough horizontal table when the block just begin slip the pulling force found to be 40N,what coefficient of friction between the two surfaces
You want the static friction coefficient in this case. It tells you the mount of friction that will start the sliding pricess. Call the coefficient Us.
40 = Weight*Us
Us = 40N/200N = 0.20
So happy
This is rubbish
To find the coefficient of friction between the two surfaces in this scenario, you can use the equation for calculating the coefficient of friction:
Coefficient of friction (μ) = Force of Friction (Ff) / Normal Force (N)
In this case, the force of friction (Ff) is equal to the pulling force required to make the block just begin to slip, which is 40N. The normal force (N) is equal to the weight of the block pressing down on the table, which is given as 200N.
So, by substituting these values into the equation, we get:
Coefficient of friction (μ) = 40N / 200N
The normal force cancels out, leaving us with:
Coefficient of friction (μ) = 0.2
Therefore, the coefficient of friction between the two surfaces is 0.2.