Posted by **ed** on Wednesday, March 9, 2011 at 10:44pm.

my son has to draw a figure with an area of 63 and a perimeter of 32.how do he go about doing it?

- math -
**Reiny**, Wednesday, March 9, 2011 at 10:49pm
what kind of figure?

circle?, square?, triangle? , rectangle?, ......

- math -
**Ms. Sue**, Wednesday, March 9, 2011 at 10:53pm
Area of a rectangle = length times width

The factors of 63 are:

3 * 21

9 * 7

Perimeter = 2 times length plus 2 times width

The rectangle can't be 3 by 21 since its perimeter would be 6 + 42

The dimensions must be 9 by 7.

(2 * 9) + (2 * 7) = 18 + 14 = 32

He needs to draw a rectangle that measures 9 by 7.

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