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July 30, 2014

July 30, 2014

Posted by **Carmen** on Wednesday, March 9, 2011 at 8:10pm.

can someone help me on this one.. am stuck

- geometry -
**Henry**, Thursday, March 10, 2011 at 10:01pmA = (b/2) *h,

Multiply the base by 2 and get:

A = b*h,

So the area is doubled.

Let's calculate the area of the given

triangle.

A(1,1), B(9,1), C(5,5).

AB = 9 - 1 = 8 = base.

(AC)^2 = (5-1)^2 + (5-1)^2,

(AC)^2 = 16 + 16 = 32,

AC = sqrt32 = 5.66.

(b/2)^2 + h^2 = (AC)^2,

4^2 + h^2 = 32,

h^2 = 32 - 16 = 16,

h = 4.

A = (b/2) * h,

A = (8/2) * 4 = 16.

Double the base:

A = (16/2) * 4 = 32.

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