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Posted by on Wednesday, March 9, 2011 at 8:10pm.

The base length of the triangle with vertices A(1,1, B(9,1), C(5,5)is multipliend by 2.Describe the effect of the change on the area.

can someone help me on this one.. am stuck

  • geometry - , Thursday, March 10, 2011 at 10:01pm

    A = (b/2) *h,
    Multiply the base by 2 and get:
    A = b*h,
    So the area is doubled.

    Let's calculate the area of the given
    triangle.

    A(1,1), B(9,1), C(5,5).

    AB = 9 - 1 = 8 = base.

    (AC)^2 = (5-1)^2 + (5-1)^2,
    (AC)^2 = 16 + 16 = 32,
    AC = sqrt32 = 5.66.

    (b/2)^2 + h^2 = (AC)^2,
    4^2 + h^2 = 32,
    h^2 = 32 - 16 = 16,
    h = 4.

    A = (b/2) * h,
    A = (8/2) * 4 = 16.

    Double the base:
    A = (16/2) * 4 = 32.

  • geometry - , Thursday, April 14, 2016 at 10:50am

    The area is multiplied by 4

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