Posted by Carmen on Wednesday, March 9, 2011 at 8:10pm.
The base length of the triangle with vertices A(1,1, B(9,1), C(5,5)is multipliend by 2.Describe the effect of the change on the area.
can someone help me on this one.. am stuck
- geometry - Henry, Thursday, March 10, 2011 at 10:01pm
A = (b/2) *h,
Multiply the base by 2 and get:
A = b*h,
So the area is doubled.
Let's calculate the area of the given
A(1,1), B(9,1), C(5,5).
AB = 9 - 1 = 8 = base.
(AC)^2 = (5-1)^2 + (5-1)^2,
(AC)^2 = 16 + 16 = 32,
AC = sqrt32 = 5.66.
(b/2)^2 + h^2 = (AC)^2,
4^2 + h^2 = 32,
h^2 = 32 - 16 = 16,
h = 4.
A = (b/2) * h,
A = (8/2) * 4 = 16.
Double the base:
A = (16/2) * 4 = 32.
Answer this Question
- Geometry - Describe the effect of each change on the perimeter and the area of ...
- Algebra - I'm stuck!! Can someone please help me with this problem?? A triangle ...
- geometry - 14. Question says that there is a triangle with a base of x units and...
- geometry - Each base of an isosceles triangle measures 42 degrees, 30'. The base...
- geometry - A right triangle has a base that is 2 more than twice the height. ...
- geometry - the hight of a triangle is four times the length of the base. find ...
- Algebra - How do you find the area of a shaded area in a triangle and assume the...
- GeOmEtRy!!! - a triangle has an area of 35 square inches. The base of the ...
- Precalculus - The sides of an isosceles triangle are 10 cm, 10 cm, and 12 cm. A ...
- Math - consider a triangle with vertices (a,b), (c,d), (e,f), with the area of ...