Posted by **Amanda** on Wednesday, March 9, 2011 at 7:27pm.

The drawing shows a version of the loop-the-loop trick for a small car. If the car is given an initial speed of 4.6 m/s, what is the largest value that the radius r can have if the car is to remain in contact with the circular track at all times

- physics -
**bobpursley**, Wednesday, March 9, 2011 at 7:49pm
at the top, mv^2/r=mg

r=v^2/g

- physics -
**bobpursley**, Wednesday, March 9, 2011 at 7:52pm
oops. Stinking thinking, I didn't read it.

at the top mv^2/r=mg

but v a the top is the initial v, minus that lost to PEnergy

vf^2=vi^2-2gh

or vf= sqrt (4.6^2-2*9.8*h)

now, to the solution

vf^2/r= g

(4.6^2-2*9.8*2r)^2 =rg

solve for r

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