0.3g of clotrimazole (C22H17ClN2) was dissolved in 80ml of anhydrous acetic acid. This was titrated with 0.1M perchloric acid using 0.3ml of naphtholbenzein as indicator until the colour changes from brownish-yellow to green.

1ml of 0.1M perchloric acid is equivalent to 34.48mg of clotrimazole (C22H17ClN2).
1st titration= A ml of 0.1M perchloric acid was used.
2nd titration= B ml of 0.1M perchloric acid was used.
How do I calculate the % of clotrimazole?

A mL x (34.48 mg cmpd/1mL) = ??mg cmpd. Convert to grams, then

(grams/0.3)*100 = %
B mL is done the same way.

To calculate the percent of clotrimazole in the solution, we need to determine the amount of clotrimazole present in each titration.

Let's begin with the information given:
- 1 ml of 0.1 M perchloric acid is equivalent to 34.48 mg of clotrimazole.

For the 1st titration (A ml of 0.1 M perchloric acid used):
The amount of clotrimazole can be calculated by multiplying the volume of perchloric acid used (A ml) by the conversion factor mentioned above.

Amount of clotrimazole in the 1st titration = A ml * 34.48 mg/ml

Similarly, for the 2nd titration (B ml of 0.1 M perchloric acid used):
Amount of clotrimazole in the 2nd titration = B ml * 34.48 mg/ml

To calculate the overall amount of clotrimazole in the solution, we sum the amounts from both titrations:

Total amount of clotrimazole = Amount in the 1st titration + Amount in the 2nd titration

Now, to find the percent of clotrimazole in the solution, we divide the total amount of clotrimazole by the initial mass of clotrimazole used (0.3 g) and multiply by 100:

Percent of clotrimazole = (Total amount of clotrimazole / Initial mass of clotrimazole) * 100

Substituting the values, we can calculate the percent of clotrimazole.