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December 20, 2014

December 20, 2014

Posted by **HELP!!** on Wednesday, March 9, 2011 at 10:34am.

f(x)= x2-7x+12/x4-8x3+13x2+30x-72

- Calculus -
**Reiny**, Wednesday, March 9, 2011 at 12:46pmSurely you meant ...

f(x) = (x^2-7x+12)/(x^4-8x^3+13x^2+30x-72)

= (x-3)(x-4)/(x^4-8x^3+13x^2+30x-72)

I checked by synthetic division if those factors are contained in the denominator, and they are, so

= 1/(x^2 - x - 6)

= (x^2 - x - 6)^-1

f '(x) = -(x^2 - x - 6)^-2 (2x-1)

= (1 - 2x)/(x^2 - x - 6)^2

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