Posted by **DMITRIC** on Wednesday, March 9, 2011 at 2:16am.

A box is lifted with a pry bar, by slipping the bar under the box and lifting up on the bar. If the pry bar is 2m in length and it is grasped at the end, and the box is located at the opposite end, the fulcrum, with its center of gravity at a distance of 0.5 m from the fulcrum.

what is the size of the force required to lift the box if the box has a weight of 100N?

CAN SOMEONE TELL ME IF I AM CORRECT?

.5 X 100 = 50Nm / 2m = 25N

- PHYSICS please HELP -
**drwls**, Wednesday, March 9, 2011 at 5:58am
0.5m * 100N = F * 2m

Solve for unknown F

F = 25 N

Right answer; bad notation.

- PHYSICS please HELP -
**DMITRIC**, Wednesday, March 9, 2011 at 8:04am
Thanks Mr. drwls for your input, but I do not follow the above notation. is * multiplication? forgive my ignorance...:(

- PHYSICS please HELP -
**Damon**, Wednesday, March 9, 2011 at 9:21am
Yes * means multiply

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