Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Calculus
Derivatives
f'(x)=(24)/((2sinx+6cosx)^2)
find equation of line y=mx+b
1 answer
Something missing here.
You can
ask a new question
or
answer this question
.
Similar Questions
Evaluate (2sinx)(3sinx) (6cosx)(cosx)
Top answer:
2*3*6 sinx*sinx cosx*cosx 36 sin^2(x) cos^2(x) or 9(2 sinx cosx)^2 9 sin^2(2x) 9/2 (1-cos(4x))
Read more.
Let f(x)=9sinx/2sinx+4cosx.
Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent
Top answer:
To find the equation of the tangent line to y = f(x) at a = 2, we need to calculate the value of
Read more.
Find the equation of the tangent line to the curve y=2sinx at the point ((pi/6), 1). The equation of the tangent line can be
Top answer:
To find the equation of the tangent line to the curve y=2sinx at the point ((pi/6), 1), we can use
Read more.
The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where f(x) =4sinx/4sinx+6cosx
i already got
Top answer:
Well, let me help you out with that! To find the value of b in the equation y = mx + b, you need to
Read more.
Find an equation of a line that is tangent to y=2sinx and whose slope is a maximum
Top answer:
The slope is a max/min when the second derivative is zero y' = 2cosx y'' = -2sinx -2sinx = 0 sinx =
Read more.
a) Find an equation of a line that is tangent to y=2sinx and whose slope is a maximum value.
b) Is there more than one solution?
Top answer:
remember that the slope of a function is the first derivative of that function. So for the slope to
Read more.
Find an equation of the tangent line to the given curve at the given point
y=(1/cosx)-2cosx at((pi/3),1) y'=0+2sinx slope = √3
Top answer:
Got it.
Read more.
Given that f(x) = 2sinx - cosx
- Write f(x) in the form Asin(x+a) - Find the maximum value of 2sinx - cosx - Find the lowest
Top answer:
how about expanding Asin(x+a) = Asinxcosa + Acosxsina so Asinxcosa + Acosxsina = 2sinx - cosx This
Read more.
find the tangent line of the following function Y=2sinx + sinx^2 at the points Pi/6,5/4
Top answer:
I think you have a typo. I'm sure you meant y = 2sinx + (sinx)^2 since y(π/6) = 2(1/2) + 1/4 = 5/4
Read more.
Let f(x)=9sinx/2sinx+4cosx
Then f'(x)=________ . The equation of the tangent line to y=f(x) at a= pi/2 can be written in the form
Top answer:
doesn't look too bad as soon as you let us know whether the denominator is 2sinx or 2sinx+4cosx (do
Read more.
Related Questions
The equation 2sinx+sqrt(3)cotx=sinx is partially solved below.
2sinx+sqrt(3)cotx=sinx sinx(2sinx+sqrt(3)cotx)=sinx(sinx)
Find the integral of 3cos2x-2sinx
a straight line passes through p(-1,1) and q(3,4)
a) find the length of line pq b) find the equation of the perpendicular
Line L is given by the equation 3y+2x =9 and point P has coordinates (6,-5).
a. Explain why point P is not on the Line L b. Find
Let f be the function defined by f(x)=2sinx+cosx ?
The average rate of change of f over the interval [0,b] is 0.05, where b>0 .
The equation of line L is y=3x–4 and is perpendicular to line H. They cross each other at the y-intercept of line L. Find the
I need help with "write in equation in slope-intercept form for the line that is parallel to to the given line line and and that
Parallel and Perpendicular Lines Equations
Find the equation of the line parallel to the line shown in the graph passing through
Use implicit differentiation to find the equation of the tangent line to the curve xy3+xy=14 at the point (7,1) . The equation
Identify the function displayed by the graph. (1 point) Responses f(x) = 6cosx f(x) = 6cosx f(x)= 6 sinx f(x)= 6 sinx f(x) =
