Tuesday

March 31, 2015

March 31, 2015

Posted by **Beth** on Wednesday, March 9, 2011 at 12:31am.

M'(x) =

3,600x−2 − 1

(3,600x−1 + x)2

.

Estimate M'(10), M'(60), and M'(110). (Round your answers to seven decimal places.)

M'(10) = 1 mpg/mph

M'(60) = 2 mpg/mph

M'(110) = 3 mpg/mph

What do the answers tell you about your car?

The results mean that at a speed of 10 mph, the fuel economy is increasing at a rate of 4 miles per gallon per 1-mph increase in speed, at a speed of 60 mph, the fuel economy is neither increasing nor decreasing, and at a speed of 110 mph, the fuel economy is decreasing at a rate of 5 miles per gallon per 1-mph increase in speed. Thus 60 mph is the most fuel-efficient speed for the car.

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