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September 20, 2014

September 20, 2014

Posted by **CMM** on Tuesday, March 8, 2011 at 10:16pm.

S= integral sign

I= absolute value

S ((cos x)/(2 + sin x))dx

Not sure if I'm doing this right:

u= 2 + sin x

du= 0 + cos x dx

= S du/u = ln IuI + C

= ln I 2 + sin x I + C

= ln (2 + sin x) + C

Another problem:

S ((sin (ln x))/(x)) dx

I don't even know what to put as u and du?

Please help with explanations.

- Calculus -
**agrin04**, Tuesday, March 8, 2011 at 10:55pmThe first problem is correct.

As for the second problem, take:

u = ln x

du = (1/x) dx

So:

S (ln u) du = ?

Try it yourself

- Calculus -
**CMM**, Tuesday, March 8, 2011 at 11:14pmWhy is it S (ln u) du = ?

What about the sin? And to multiply them are you reciprocating?

- Calculus -
**agrin04**, Tuesday, March 8, 2011 at 11:52pmOh sorry. It should be:

S sin(u) du

- Calculus -
**CMM**, Wednesday, March 9, 2011 at 1:08amSo I get this:

= ln Isin(u)I + C

= ln Isin(ln x)I + C

= ln (sin(ln x)) + C

OR

= ln (sin(1/x)) + C

Is it correct or incorrect?

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