Posted by CMM on Tuesday, March 8, 2011 at 10:16pm.
The first problem is correct.
As for the second problem, take:
u = ln x
du = (1/x) dx
S (ln u) du = ?
Try it yourself
Why is it S (ln u) du = ?
What about the sin? And to multiply them are you reciprocating?
Oh sorry. It should be:
S sin(u) du
So I get this:
= ln Isin(u)I + C
= ln Isin(ln x)I + C
= ln (sin(ln x)) + C
= ln (sin(1/x)) + C
Is it correct or incorrect?
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