Posted by CMM on Tuesday, March 8, 2011 at 10:16pm.
Evaluate the integral.
S= integral sign
I= absolute value
S ((cos x)/(2 + sin x))dx
Not sure if I'm doing this right:
u= 2 + sin x
du= 0 + cos x dx
= S du/u = ln IuI + C
= ln I 2 + sin x I + C
= ln (2 + sin x) + C
S ((sin (ln x))/(x)) dx
I don't even know what to put as u and du?
Please help with explanations.
- Calculus - agrin04, Tuesday, March 8, 2011 at 10:55pm
The first problem is correct.
As for the second problem, take:
u = ln x
du = (1/x) dx
S (ln u) du = ?
Try it yourself
- Calculus - CMM, Tuesday, March 8, 2011 at 11:14pm
Why is it S (ln u) du = ?
What about the sin? And to multiply them are you reciprocating?
- Calculus - agrin04, Tuesday, March 8, 2011 at 11:52pm
Oh sorry. It should be:
S sin(u) du
- Calculus - CMM, Wednesday, March 9, 2011 at 1:08am
So I get this:
= ln Isin(u)I + C
= ln Isin(ln x)I + C
= ln (sin(ln x)) + C
= ln (sin(1/x)) + C
Is it correct or incorrect?
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