Calculus
posted by Sal on .
The area of largest isosceles triangle that can be drawn with one vertex at the origin and with others on a line parallel to and above the xaxis and on the curve y=27x^2 is....
A) 108
B) 27
C) 12 root 3
D) 54
E) 24 root 3

D) 54
One vertex is x,y and the other is x,y
y= 27  x^2
A= 1/2 BxH
B = x  x = 2x
H = 27  x^2
A = 1/2 * 2x * (27  x^2)
Take the derivative, find when the derivative is = 0 then plug that back in to get dimensions and solve for area.