How many moles of ammonia gas can be produced from the reaction of 3.0L of N2 and 3.0L of H2 according to the following equation:

N2(g) + 3H2(g)---> 2NH3(g)?

You have a limiting reagent problem. In gaseous reactions you may use L as if they were moles.

Using the coefficients in the balanced equation, convert L N2 to L NH3. Do the same for L H2 to L NH3. The two answers won't be the same; the correct value in limiting reagent problems is ALWAYS the smaller one and the reagent producing that value is the limiting reagent. Take the smaller value (in L) and convert to moles remembers that 1 mole of a gas occupies 22.4 L at STP.

To determine the number of moles of ammonia gas produced, we need to use the concept of stoichiometry and the given volume of nitrogen gas (N2) and hydrogen gas (H2).

First, let's convert the given volumes of nitrogen gas and hydrogen gas to moles using the ideal gas law equation:

PV = nRT

Where:
P = pressure of the gas (assume constant)
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant
T = temperature (assume constant)

Since the temperature and pressure are assumed to be constant, we can rewrite the equation as:

(Volume of gas) = (Number of moles of gas) x (ideal gas constant)

Now, let's calculate the number of moles of N2 and H2:

Number of moles of N2 = (Volume of N2) / (Volume constant)
Number of moles of H2 = (Volume of H2) / (Volume constant)

Next, we need to determine the stoichiometric ratio between the reactants and products according to the balanced chemical equation:

N2(g) + 3H2(g) ---> 2NH3(g)

From the balanced equation, we can see that one mole of N2 reacts with three moles of H2 to produce two moles of NH3.

Using the stoichiometric ratio, we can now determine the limiting reactant. The limiting reactant is the reactant that would be completely consumed in the reaction. The reactant that produces fewer moles of the desired product (in this case, ammonia) will be the limiting reactant.

To find the limiting reactant, we compare the number of moles of each reactant to the stoichiometric ratio. Assume we have x moles of N2 and y moles of H2.

Number of moles of NH3 that can be produced from N2 = (x moles of N2) * (2 moles of NH3 / 1 mole of N2)
Number of moles of NH3 that can be produced from H2 = (y moles of H2) * (2 moles of NH3 / 3 moles of H2)

Compare these two quantities and find the smaller value. Whichever value is smaller will be the limiting reactant.

Now, knowing the limiting reactant, we can find the number of moles of ammonia gas produced using the stoichiometric ratio between the limiting reactant and the desired product.

Number of moles of NH3 produced = (Number of moles of limiting reactant) * (2 moles of NH3 / number of moles of limiting reactant)

Once you have the number of moles of ammonia gas produced, you can calculate the final answer.