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September 3, 2014

September 3, 2014

Posted by **Zukii** on Tuesday, March 8, 2011 at 9:20pm.

a) ln(√sinx)

- Calculus -
**MathMate**, Tuesday, March 8, 2011 at 10:25pmUse the chain rule:

d(ln(√sin(x)))/dx

=[1/(√sin(x))]*d√(sin(x))/dx

=[1/(√sin(x))]*[1/(2√(sin(x)))]*d(sin(x))/dx

=[1/(√sin(x))]*[1/(2√(sin(x)))]*cos(x)

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