Posted by Zukii on Tuesday, March 8, 2011 at 9:20pm.
Use the chain rule:
d(ln(√sin(x)))/dx
=[1/(√sin(x))]*d√(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*d(sin(x))/dx
=[1/(√sin(x))]*[1/(2√(sin(x)))]*cos(x)
Related Questions
Math - Derivatives - Differentiate the given function. Simplify the answer. f(x...
Calculus - Differentiate the following function: y= [x+1]/√x I tried y...
calculus - I have been asked to solve this two different ways. The first way is...
Math differentiation - Can somebody please check these over for me? I really ...
Calculus - How do I differentiate ln (2X^2 - 12X + Y^2 -10Y) and the second ...
calculus - hi, just wondering on how i should approach differentiating: loge1/(3...
Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...
Calculus - I think I have the correct answers for the following problems. For ...
calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...
calculus - Use fundamental identities to simplify the expression sinx+1 + 1/sinx...
For Further Reading