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Calculus

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Differentiate the following ( do not simplify)
a) ln(√sinx)

  • Calculus - ,

    Use the chain rule:
    d(ln(√sin(x)))/dx
    =[1/(√sin(x))]*d√(sin(x))/dx
    =[1/(√sin(x))]*[1/(2√(sin(x)))]*d(sin(x))/dx
    =[1/(√sin(x))]*[1/(2√(sin(x)))]*cos(x)

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