What volume of 0.0500 M Ba(OH)2 will react completely with 29.50 mL of 0.350 M HCl?
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O
moles HCl = M x L = ??
moles Ba(OH)2 = 1/2 that (from the coefficients).
Then M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2
moles HCl = M x L = ??
moles Ba(OH)2 = 1/2 that (from the coefficients).
Then M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2