Posted by Jessica on Tuesday, March 8, 2011 at 12:56pm.
The simplest solution is by factorization:
y^2-4y-12=0
(y 2)(y 6)=0
Since 2*6=12, 6-2=4
are what you are looking for.
Now we need to figure out the signs:
-12 means that exactly one of the constants (2 or 6) carry a negative sign.
If we give assign 2 and -6, we get 2-6=-4, which is what we want, so:
(y+2)(y-6)=0
Can you do take it from here?
In google type:
"quadratic equation online"
When you see list of results click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
In rectacangle type: y^2-4y-12=0
and click option solve it
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