Posted by Tina on Tuesday, March 8, 2011 at 1:28am.
The curve intersects the x-axis at (1,0) and (-1,0).
Volume = π[integral] y^2 dx from -1 to 1
or by symmetry
= 2π[integral] (9-9x^2)^2 dx from 0 to 1
= 2π[integral] (81 - 162x^2 + 81x^4) dx from 0 to 1
= 2π(81x - 54x^3 + (81/5)x^5) from 0 to 1
= 2π(81 - 54 + 81/5 - 0)
= 432π/5
Related Questions
calculus - Consider the solid obtained by rotating the region bounded by the ...
Calculus [rotation of region bounded by curves] - Find the volume of the solid ...
Calculus II - Consider the solid obtained by rotating the region bounded by the ...
calculus - Consider the solid obtained by rotating the region bounded by the ...
Calculus - Consider the region bounded by the curves y=e^x, y=-e^x, and x=1. Use...
CALCULUS 2 - Consider the solid obtained by rotating the region bounded by the ...
calculus - Consider the solid obtained by rotating the region bounded by the ...
calculus - Consider the solid obtained by rotating the region bounded by the ...
Calculus - Find the volume of the solid obtained by rotating the region bounded...
CALCULUS:) - Find the volume of the solid obtained by rotating the region ...
For Further Reading