Posted by **Anonymous** on Monday, March 7, 2011 at 9:26pm.

Formulate but do not solve the problem.

A theater has a seating capacity of 840 and charges $4 for children (x), $6 for students (y), and $8 for adults (z). At a certain screening with full attendance, there were half as many adults as children and students combined. The receipts totaled $5000. How many children attended the show?

= 840

= z

= 5000

## Answer this Question

## Related Questions

- math - Formulate a system of equations for the situation below and solve. A ...
- math - a theater seating 300 charges $1 for children $2 for students and $5 for...
- math - Write the answer to the problem as an algebraic expression. A theater ...
- Algebra - Write the answer to the problem as an algebraic expression. A theater ...
- Math - A movie theater charges $6 for each adult and $3 for each child. If the ...
- math/probability - For some reason I can not get my head around probability. ...
- algebra - A movie theater charges $6 for an adult and $3 for a child. if the ...
- Math - 3/4 of the seats in a school bus were occupied. after 3 students got off ...
- Math - Write the answer to the problem as an algebraic expression. (Tell how you...
- Algebra - A theater ticket for adults is a dollars and the price of a child's ...

More Related Questions