Thursday

November 27, 2014

November 27, 2014

Posted by **ashley --- HELP PLEASEE!!!** on Monday, March 7, 2011 at 8:47pm.

- physics -- projectile motion -
**jai**, Monday, March 7, 2011 at 8:59pmrecall that the formula for range is:

R = (vo)^2 * sin (2*theta) / (2g)

where

vo = initial velocity

theta = angle of release

g = acceleration due to gravity (9.8 m/s^2)

now, if we're given the initial velocity, the value of range will depend on theta,, observing this, if we want to have a max Range, we have to find the max value of sin (2*theta),, but the max value of sine is always 1, therefore, equating this to 1:

sin (2*theta) = 1

2*theta = arcsin 1

2*theta = 90 degrees

theta = 45 degrees

hope this helps~ :)

- physics -- projectile motion -
**jai**, Monday, March 7, 2011 at 9:04pmoops, sorry the formula for range must be

R = (vo)^2 * sin (2*theta) / g

i just remembered that the 2g is for the max height:

h,max = (vo)^2 * [sin (theta)]^2 / 2g

but explanation and proving is still the same~ :)

- physics -- projectile motion -
**John**, Monday, August 29, 2011 at 4:46amthe greatest sin value of theta is the sin of 45*

**Answer this Question**

**Related Questions**

Physics - Range of projectile motion - What properties of projectile motion must...

Physics - Projectile Motion - This is going to be hard to explain, but I did an ...

Physics - For a given initial projectile speed, you observe that the projectile ...

Physics - A projectile is launched at an angle of 34.0o above the horizontal. ...

Physics - Q Exactly 2.7s after a projectile is fired into the air from the ...

physics - an astronaut on the moon fires a projectile from a launcher on a level...

Physics - The projectile motion is fired with velocity of magnitude vo at the ...

Physics - The projectile motion is fired with velocity of magnitude vo at the ...

Calculus (Gr.12) Math - I am not sure how to do this question I know I have to ...

physics - The range R of a projectile is defined as the magnitude of the ...