Sunday

March 1, 2015

March 1, 2015

Posted by **Ryan** on Monday, March 7, 2011 at 8:04pm.

I had the shell radius as (6-x) and the shell height as (4x-2x^2).

My final integral was 2 pi * integral from 0 to 2 of [(6-x)(4x-2x^2)]. I was just wondering if I did this correct? Thanks.

- Calculus -
**MathMate**, Monday, March 7, 2011 at 9:29pmYes, your expressions for the radius and the height are correct. The expression to integrate as well. The shell method evaluates basically ∫2πr(x)h(x)dx. The limits have not been stated in the question, but I suppose they are from x=0 to x=2, as you put it.

Good work!

**Answer this Question**

**Related Questions**

calculus - Use the shell method to set up and evaluate the integral that gives ...

Math (Calculus) - Use the shell method to set up and evaluate the integral that ...

calculus - Use the shell method to set up and evaluate the integral that gives ...

calculus - Use the disk or the shell method to find the volume of the solid ...

calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...

calculus - 2. Let R be the region in the first quadrant bounded by the graphs of...

calculus - 2. Let R be the region in the first quadrant bounded by the graphs of...

calculus - Use the disk or the shell method to find the volume of the solid ...

Math (Calculus) - Find the volume of the solid generated by revolving the region...

Math (Calculus) - Use the disc method to find the volume of the solid generated ...