Posted by maya on Monday, March 7, 2011 at 6:01pm.
the floor of a room is a rectangle. it has a perimeter of 22m and an area of 24 square meters.
what are the length and width of the room?
- math - Reiny, Monday, March 7, 2011 at 6:06pm
length --- x
width --- y
x+y = 11 or y = 11-x
xy = 24
x(11-x) = 24
x^2 - 11x + 24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
if x=3, y = 8
if x = 8, y = 3
the room is 3 by 8
- math - Ms. Sue, Monday, March 7, 2011 at 6:07pm
This must be a closet.
The factors of 24:
3 * 8
4 * 6
2 * 12
Which of those dimensions would give a perimeter of 22 m?
- math - maya, Monday, March 7, 2011 at 6:15pm
im in grade 4 i dont know what that is
- math - Ms. Sue, Monday, March 7, 2011 at 6:16pm
Perimeter = 2 times length plus 2 times width
- math - maya, Monday, March 7, 2011 at 6:17pm
rieny that doesent make sense it cant be.
- math - Reiny, Monday, March 7, 2011 at 6:17pm
Maya, if you only in grade 4, then forget about my solution.
Go with what Ms Sue has shown you.
the room is 3 metres by 8 metres
check : 3+8 + 3+8 = 22
3x8 = 24
- math - maya, Monday, March 7, 2011 at 6:21pm
wow thanks rieny :)
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