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Posted by **maya** on Monday, March 7, 2011 at 6:01pm.

what are the length and width of the room?

- math -
**Reiny**, Monday, March 7, 2011 at 6:06pmlength --- x

width --- y

x+y = 11 or y = 11-x

xy = 24

x(11-x) = 24

x^2 - 11x + 24 = 0

(x-3)(x-8) = 0

x = 3 or x = 8

if x=3, y = 8

if x = 8, y = 3

the room is 3 by 8

- math -
**Ms. Sue**, Monday, March 7, 2011 at 6:07pmThis must be a closet.

The factors of 24:

3 * 8

4 * 6

2 * 12

Which of those dimensions would give a perimeter of 22 m?

- math -
**maya**, Monday, March 7, 2011 at 6:15pmim in grade 4 i dont know what that is

- math -
**maya**, Monday, March 7, 2011 at 6:15pmim in grade 4 i dont know what that is

- math -
**Ms. Sue**, Monday, March 7, 2011 at 6:16pmPerimeter = 2 times length plus 2 times width

- math -
**maya**, Monday, March 7, 2011 at 6:17pmrieny that doesent make sense it cant be.

- math -
**Reiny**, Monday, March 7, 2011 at 6:17pmMaya, if you only in grade 4, then forget about my solution.

Go with what Ms Sue has shown you.

the room is 3 metres by 8 metres

check : 3+8 + 3+8 = 22

3x8 = 24

- math -
**maya**, Monday, March 7, 2011 at 6:21pmwow thanks rieny :)

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