Homework Help: Physics

Posted by Randy on Monday, March 7, 2011 at 1:04am.

When you push a 1.82-kg book resting on a tabletop, it takes 2.30 N to start the book sliding. Once it is sliding, however, it takes only 1.46 N to keep the book moving with constant speed.
Q1. What is the coefficient of static friction between the book and the tabletop?
Q2. What is the coefficient of kinetic friction between the book and the tabletop?

Physics - drwls, Monday, March 7, 2011 at 4:37am
Q1: 2.30 = M*g*mus

mus = 2.30/(M*g) = 0.129

Q2: 1.46 = M*g*muk

muk = 1.46/(M*g) = ___

Answer this Question

Related Questions

physics - When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to ...
physics - When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to ...
physics - When you push a 1.55 kg book resting on a tabletop it takes 2.10 N to ...
phy - When you push a 1.82-{\rm kg} book resting on a tabletop, it takes 2.21 N ...
physics - When you push a 1.55 kg block resting on a tabletop it takes 1.85 N to...
physics - When you push a 2.05 kg book resting on a tabletop it takes 2.45 N to ...
physics - When you push a 1.95 kg book resting on a tabletop it takes 2.40 N to ...
physics - I keep geting this question wrong and cant figure out what i am doing ...
Physics - When you push a 1.80-kg book resting on a tabletop, it takes 2.05 N to...
Science - You push a book on a table so that its velocity is constant. If the ...

For Further Reading

First Name:
School Subject:
Answer: