Monday

October 20, 2014

October 20, 2014

Posted by **Bill** on Sunday, March 6, 2011 at 11:34pm.

- Algebra/geometry -
**jai**, Monday, March 7, 2011 at 9:38amlet x = length of the original rectangle

let x-4 = width of the original rectangle

using the conditions given by the 2nd statement,

new width: (x-4) + 5

new length: x - 3

using the next condition given in the problem, and recalling that the area of a rectangle is just length*width:

(x-3)[(x-4) + 5] = 177

(x-3)(x+1) - 177 = 0

expanding this using FOIL:

x^2 - 2x - 3 - 177 = 0

x^2 - 2x - 180 = 0

we see that this one's not factorable,, so you use quadratic formula~

hope this helps :)

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