Posted by DMITRIC on .
A CIRCULAR SAW BLADE ROTATING AT 15 REV/S IS BROUGHT TO A STOP IN 125 REV.
WHAT IS THE VALUE OF WO IN RAD/S?
94.2 RAD/S
WHAT IS THE SIZE OF THE DISPLACEMENT, TEITA, IN RADIANS?
WHAT IS THE SIZE OF THE ANGULAR ACCELERATION EXPERIENCED?
HOW LONG DID IT TAKE FOR THE SAW BLADE TO COME TO REST?

PHYSICS 
Damon,
15*2 pi = 30 pi = 94.2 sure enough
average w during stop = wo/2 = 47.1 or 7.5 rev/s
time to stop = 125/7.5 = 16.7 seconds
w = wo + a t
0 = 94.2 + a (16.7)
so
a = 5.65 rad/s^2
so
theta = wo t + (1/2) a t^2
= 94.2 (16.7)  2.83 * 16.7^2
1573  789
= 784 radians